矢量定义#

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Dm $ddd$

$$ \frac{x+y}{z} \cdot \times (x, y) $$

^8fd4f9 $$ 2^{2} \equiv \neq \to $$ $$ xyz \vec{i} \vec{j} \vec{k} $$

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lemma content

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$$ \begin{equation} % 定理环境

任意大于2的偶数可表为两素数之和（哥德巴赫猜想） \end{equation} $$ \begin{proof}@[[]] [[#^8fd4f9]] [[#^f94ca0]]

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[!lemma|*] Title Content

[!def|A.1] Title Content

%% label: my-theorem %% %% display: My Awesome Theorem %% %% main %%

%% label: my-theorem %% %% display: My Awesome Theorem %% %% main %%

%% label: my-theorem display: My Awesome Theorem main: true %%

$$ $$ \alpha \beta \gamma $$

$$ \begin{pmatrix} sdfsd \end{pmatrix} \begin{pmatrix} 1 & 2 & 3 \ 4 & 5 & 6 \ 7 & 8 & 9 \end{pmatrix} $$

$$ \begin{equation} \begin{aligned} f\colon \mathbb{R} &\longrightarrow \mathbb{C} \ x &\longmapsto f(x) = x^{2} \end{aligned} \end{equation} $$

$$ \begin{bmatrix}\frac{\partial g_1}{\partial y_1}&\frac{\partial g_1}{\partial y_2}&\cdots&\frac{\partial g_1}{\partial y_l}\\frac{\partial g_2}{\partial y_1}&\frac{\partial g_2}{\partial y_2}&\cdots&\frac{\partial g_2}{\partial y_l}\\vdots&\vdots&\ddots&\vdots\\frac{\partial g_k}{\partial y_1}&\frac{\partial g_k}{\partial y_2}&\cdots&\frac{\partial g_k}{\partial y_l}\end{bmatrix} $$